BIN Bin making process (1 Viewer)

[sam101011]

​

This is a complex, but very good to generate lives. Very few people know it, since it was extracted from a bank's SoFlA card generation software
b10 * sum:

T1: 4915 1101 7692 8790
T2: 4915 1101 9176 8499

For this method, we must use only the 10 digits of two CCs. But, how do I do if the CCs have different numbers?

OK:

From the third group, only the 2 numbers in the middle will be used:
4915 1101 x69x xxxx
4915 1101 x17x xxxx

They are added:
6 + 1 = 07
9 + 7 = 16

From these results, the number is divided by 2

6 + 1 = 7 = 3.5
9 + 7 = 16 = 08

Then, multiply by 5.

6 + 1 = 7 = 3.5 = 17.5
9 + 7 = 16 = 08 = 40

If there is a decimal (.?) And the number is two digits, the decimal is deleted.
And the result is added:

17 + 40 = 57

So I would finish

4915 1101 57xx xxxx

Logical indentation:
4915 1101 7692 8790

We must separate the first 6 numbers of the CC:
[491511] | [0176928790]

And, they will be fixed in the second group:
[0176928790]

Afterwards, this group must separate it in mode (3-4-3), that is:
[017] [6928] [790]
And, eliminate the central number:
[0x7] [6xx8] [7x0]

Then, they order the BIN with the rest:

Final Result: 4915110x76xx87x0

MaTerialDInVerter:

This is a private algorithm which affects the cards generated after mid-2017, it was taken from the SoFlA software of Banco de Bogota.

This is the most, most complex of all and has a 100% certainty of taking lives if you use it well.

This method requires 2 CCs, which are commonly issued between October 2016 and February 2017

So:
T1: 4915 1101 7692 8790
T2: 4915 1101 9176 8499

You have to separate T1 and T2 into 2 groups of 8 digits:

T1: [49151101]
[76928790]
T2: [49151101]
[91768499]
Now, you are going to grab T2 and you are going to order it in the following way:

1st group x 2nd group
4 x 9
9 x 1
1 x 7
5 x 6
1 x 8
1 x 4
0 x 9
1 x 9

And multiply it:
4 x 9 = 36
9 x 1 = 9
1 x 7 = 7
5 x 6 = 30
1 x 8 = 8
1 x 4 = 4
0 x 9 = 0
1 x 9 = 9

Link:

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[jieke88]

​

这是一个复杂的，但是很好地生成生命的过程。很少有人知道它，因为它是从银行的 SoFlA 卡生成软件中提取的
b10 * 总和：

电话：4915 1101 7692 8790
电话2：4915 1101 9176 8499

对于此方法，我们必须仅使用两个 CC 的 10 位数字。但是，如果CC的编号不同怎么办？

好的：

从第三组开始，只使用中间的 2 个数字：
4915 1101 x69xxxx
4915 1101 x17x xxxx

它们被添加：
6 + 1 = 07
9 + 7 = 16

根据这些结果，该数字除以 2

6 + 1 = 7 = 3.5
9 + 7 = 16 = 08

然后乘以 5。

6 + 1 = 7 = 3.5 = 17.5
9 + 7 = 16 = 08 = 40

如果有小数点（.?）且数字为两位数，则删除小数点。
并添加结果：

17 + 40 = 57

所以我会完成

4915 1101 57xxxxx

逻辑缩进：
4915 1101 7692 8790

我们必须将 CC 的前 6 个数字分开：
[491511] | [0176928790]

并且，它们将固定在第二组中：
[0176928790]

之后，该组必须以模式（3-4-3）将其分开，即：
[017][6928][790]
并且，消除中心数：
[0x7] [6xx8] [7x0]

然后，他们将 BIN 与其余的一起订购：

最终结果：4915110x76xx87x0

材料DInverter：

这是一个私人算法，影响 2017 年中之后生成的卡，它取自波哥大银行的 SoFlA 软件。

这是最复杂的，如果使用得当，100% 肯定会夺走生命。

此方法需要2个CC，一般在2016年10月至2017年2月期间签发

所以：
电话：4915 1101 7692 8790
电话2：4915 1101 9176 8499

您必须将 T1 和 T2 分成 2 组 8 位数字：

T1：[49151101]
[76928790]
T2：[49151101]
[91768499]
现在，您要购买T2，并按以下方式订购：

第一组×第二组
4×9
9×1
1×7
5×6
1×8
1×4
0×9
1×9

放置其相乘：
4×9 = 36
9 x 1 = 9
1×7 = 7
5 x 6 = 30
1×8 = 8
1×4 = 4
0×9 = 0
1×9 = 9

关联：
*** 隐藏文本：无法引用。***
​

​

这是一个复杂的，但是很好地生成生命的过程。很少有人知道它，因为它是从银行的 SoFlA 卡生成软件中提取的
b10 * 总和：

电话：4915 1101 7692 8790
电话2：4915 1101 9176 8499

对于这个方法，我们但是只能使用两个CC的10位数字。，如果CC的编号不同怎么办？

好的：

从第三组开始，只使用中间的2个数字：
4915 1101x69xxxx
4915 1101 x17x xxxx

它们被添加：
6 + 1 = 07
9 + 7 = 16

根据这些结果，该数字除以 2

6 + 1 = 7 = 3.5
9 + 7 = 16 = 08

然后乘以5。

6 + 1 = 7 = 3.5 = 17.5
9 + 7 = 16 = 08 = 40

如果有小数点（.?）且数字为这三个数，则删除小数点。
并添加结果：

17 + 40 = 57

所以我会完成

4915 1101 57xxxxx

逻辑缩进：
4915 1101 7692 8790

我们必须将CC的前6个数字分开：
[491511] | [0176928790]

并且，他们将固定在第二组中：
[0176928790]

随后，该组必须以模式（3-4-3）将其分开，即：
[017][6928][790]
并且，去除中心数：
[0x7] [6xx8] [7x0]

然后，他们将BIN与其余的一起整理：

最终结果：4915110x76xx87x0

材料D逆变器：

这是一个私人算法，影响2017年中之后生成的卡，它取自波哥大银行的SoFlA软件。

这是最复杂的，如果用得当，100%肯定会夺走生命。

此方法需要2个CC，一般在2016年10月至2017年2月期间签发

所以：
电话：4915 1101 7692 8790
电话2：4915 1101 9176 8499

您必须将 T1 和 T2 串联 2 组 8 位数字：

T1：[49151101]
[76928790]
T2：[49151101]
[91768499]
现在，您要购买T2，并按以下方式订购：

第一组×第二组
4×9
9×1
1×7
5×6
1×8
1×4
0×9
1×9

放置其相乘：
4×9 = 36
9 x 1 = 9
1×7 = 7
5 x 6 = 30
1×8 = 8
1×4 = 4
0×9 = 0
1×9 = 9

关联：
*** 隐藏文本：无法引用。***
​

这是一个有趣的话题，我很感兴趣，我会花时间研究一下
。
那么这个算法在2023-2028年是否还有用呢？

 

[Shivambruto]

Bcsdev im

 

[Shivambruto]

Gbkml

 

[bccijci25]

​

This is a complex, but very good to generate lives. Very few people know it, since it was extracted from a bank's SoFlA card generation software
b10 * sum:

T1: 4915 1101 7692 8790
T2: 4915 1101 9176 8499

For this method, we must use only the 10 digits of two CCs. But, how do I do if the CCs have different numbers?

OK:

From the third group, only the 2 numbers in the middle will be used:
4915 1101 x69x xxxx
4915 1101 x17x xxxx

They are added:
6 + 1 = 07
9 + 7 = 16

From these results, the number is divided by 2

6 + 1 = 7 = 3.5
9 + 7 = 16 = 08

Then, multiply by 5.

6 + 1 = 7 = 3.5 = 17.5
9 + 7 = 16 = 08 = 40

If there is a decimal (.?) And the number is two digits, the decimal is deleted.
And the result is added:

17 + 40 = 57

So I would finish

4915 1101 57xx xxxx

Logical indentation:
4915 1101 7692 8790

We must separate the first 6 numbers of the CC:
[491511] | [0176928790]

And, they will be fixed in the second group:
[0176928790]

Afterwards, this group must separate it in mode (3-4-3), that is:
[017] [6928] [790]
And, eliminate the central number:
[0x7] [6xx8] [7x0]

Then, they order the BIN with the rest:

Final Result: 4915110x76xx87x0

MaTerialDInVerter:

This is a private algorithm which affects the cards generated after mid-2017, it was taken from the SoFlA software of Banco de Bogota.

This is the most, most complex of all and has a 100% certainty of taking lives if you use it well.

This method requires 2 CCs, which are commonly issued between October 2016 and February 2017

So:
T1: 4915 1101 7692 8790
T2: 4915 1101 9176 8499

You have to separate T1 and T2 into 2 groups of 8 digits:

T1: [49151101]
[76928790]
T2: [49151101]
[91768499]
Now, you are going to grab T2 and you are going to order it in the following way:

1st group x 2nd group
4 x 9
9 x 1
1 x 7
5 x 6
1 x 8
1 x 4
0 x 9
1 x 9

And multiply it:
4 x 9 = 36
9 x 1 = 9
1 x 7 = 7
5 x 6 = 30
1 x 8 = 8
1 x 4 = 4
0 x 9 = 0
1 x 9 = 9

Link:
*** Hidden text: cannot be quoted. ***
​

ggf

 

[Nightfire27]

Does this kinda works?

 

[young_boss]

​

Este es un sistema complejo, pero muy bueno para generar vidas. Muy poca gente lo conoce, ya que fue extraído de un software de generación de tarjetas SoFlA de un banco.
b10 * suma:

Teléfono: 4915 1101 7692 8790
Teléfono: 4915 1101 9176 8499

Para este método, debemos utilizar únicamente los 10 dígitos de dos CC. Pero, ¿cómo hago si las CC tienen números diferentes?

DE ACUERDO:

Del tercer grupo se utilizarán únicamente los 2 números del medio:
4915 1101 x69x xxxx
4915 1101 x17x xxx

Se añaden:
6 + 1 = 07
9 + 7 = 16

A partir de estos resultados, el número se divide por 2.

6 + 1 = 7 = 3,5
9 + 7 = 16 = 08

Luego multiplica por 5.

6 + 1 = 7 = 3,5 = 17,5
9 + 7 = 16 = 08 = 40

Si hay un decimal (.?) y el número tiene dos dígitos, se elimina el decimal.
Y el resultado se añade:

17 + 40 = 57

Así que terminaría

4915 1101 57xx xxxxx

Sangría lógica:
4915 1101 7692 8790

Debemos separar los primeros 6 números del CC:
[491511] | [0176928790]

Y, se fijarán en el segundo grupo:
[0176928790]

Posteriormente este grupo debe separarlo en modo (3-4-3), es decir:
[017] [6928] [790]
Y, elimina el número central:
[0x7] [6xx8] [7x0]

Luego ordenan el BIN con el resto:

Resultado final: 4915110x76xx87x0

Inversor de material:

Este es un algoritmo privado que afecta a las tarjetas generadas a partir de mediados de 2017, fue tomado del software SoFlA del Banco de Bogotá.

Este es el más complejo de todos y tiene un 100% de certeza de cobrar vidas si lo usas bien.

Este método requiere 2 CC, que normalmente se emiten entre octubre de 2016 y febrero de 2017.

Entonces:
Teléfono: 4915 1101 7692 8790
Teléfono: 4915 1101 9176 8499

Debes separar T1 y T2 en 2 grupos de 8 dígitos:

T1: [49151101]
[76928790]
T2: [49151101]
[91768499]
Ahora, vas a coger el T2 y lo vas a ordenar de la siguiente manera:

1er grupo x 2do grupo
4 x 9
9 x 1
1 x 7
5 x 6
1 x 8
1 x 4
0 x 9
1 x 9

Y lo multiplicamos:
4 x 9 = 36
9 x 1 = 9
1 x 7 = 7
5 x 6 = 30
1 x 8 = 8
1 x 4 = 4
0 x 9 = 0
1 x 9 = 9

Enlace:
***Texto oculto: no se puede citar.***
​

yooooooo